Definition: This calculator computes the volume and circumference of a sphere, a perfectly round three-dimensional object, based on its radius (\( r \)).
Purpose: Useful in geometry, physics, and engineering for determining the volume and circumference of spherical objects (e.g., balls, planets).
The calculations are based on the following formulas:
Unit Conversions:
Details: Calculating the volume and circumference of a sphere is essential in physics (e.g., calculating planetary volumes), engineering (e.g., designing spherical containers), and everyday applications (e.g., determining the capacity of spherical objects).
Tips: Enter the radius \( r \) in mm, cm, m, in, or ft (must be >0). The result shows the volume in cm³, m³, in³, ft³, and liters, and the circumference in cm, m, in, and ft.
Given: Radius \( r = 5 \, \text{cm} \).
Volume Calculation: \( V = \frac{4}{3} \times \pi \times 5^3 \approx 523.599 \, \text{cm}^3 \).
Circumference Calculation: \( \text{Circumference} = 2 \times \pi \times 5 \approx 31.416 \, \text{cm} \).
Conversions (Volume):
- \( \text{cm}^3 \approx 523.599 \),
- \( \text{m}^3 \approx 0.000524 \),
- \( \text{in}^3 \approx 31.942 \),
- \( \text{ft}^3 \approx 0.0185 \),
- \( \text{liters} \approx 0.524 \).
Conversions (Circumference):
- \( \text{cm} \approx 31.416 \),
- \( \text{m} \approx 0.314 \),
- \( \text{in} \approx 12.368 \),
- \( \text{ft} \approx 1.031 \).